Dice

Brute Force Maths, Solving Any Dice

While trying to solve the opposing face for what I’ve dubbed as “Butterfly” configured dice, I had a bit of an epiphany and realised all my recent dice problems could be brute forced by exploiting zero to a power, that 00 equals 1 but 0¹ ᵒʳ ᵍʳᵉᵃᵗᵉʳ equals 0 allows us to essentially conditionally select what result we get from an input. The trick gives us an If statement without the notation, we can cheat around my self imposed no-ifs rule.

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Solving “Left Handed” Turned Dice

Revisiting my post about solving the opposing face of various dice configurations I pondered how a “left handed” turned dice might work. Say rather than placing five and six at the top and bottom of the dice, what if the medieval maker placed one and two in their place, then spiralling around the outside, three, four, five, six? Can we leverage our previous monster of an equation to solve it?

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Oddly Configured Dice; Finding the Opposing Face

On common six sided dice, all opposing faces add to seven (this configuration is called “sevens”). Knowing this, you can always find the value of the opposing face with the simple equation; 7 – x = y, where x is the known face and y is the opposing.

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Substituting Games Workshop Scatter & Artillery Dice with a Standard D10

Here’s a system to use a single D10 dice (the kind that “points” a direction when at rest) as substitute for a set of Games Workshop (GW) Scatter & Artillery Dice (the kind used for Warhammer Fantasy 5th Ed.). This system is long-winded, daft and best ignored. If you need to substitute some lost Scatter & Artillery Dice, just use regular D6s.

To begin let us lay out possible results of the two proprietary GW dice, each dice has 6 faces.

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